If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3a^2-10a+3=0
a = 3; b = -10; c = +3;
Δ = b2-4ac
Δ = -102-4·3·3
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-8}{2*3}=\frac{2}{6} =1/3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+8}{2*3}=\frac{18}{6} =3 $
| (3x-34)=(x+22) | | 2^3x=4x2^5x | | (5x-24)=(3x+16) | | (3/7)^3x+2x(7/3)−4=(3^x+10 | | 4(3z-2)=64 | | -12(x-4)=72 | | 8(s-2)=24 | | 3/5x+1/x=1/2 | | 3x-9(3x-9)=(2x+2)(2x+2+25) | | 1/4k=8.25 | | -6=y+y+4 | | 9=3x–2 | | (1/4)k=8.25 | | 9k=225 | | 8=2c-7-7c | | 75=(40)t-5t^2 | | -9-3a=24 | | 7x+41=(12×-19)x2 | | 7x+41=(12×-19)2 | | 8z+10=-14 | | 32^3x=64^-3x | | 4x+10=-3x-10 | | x+64=−27 | | 9x+24=-6x-6 | | -8a+3=-8a+9 | | -7a+1=-3a+9 | | 20x3^x=10 | | 14k-2(3k-5)=-62 | | 3(b-1)+2(b+3)=13 | | (4x+19)=(6x+9) | | (12-y)/2y=0 | | 6(4y-3)+2y=34 |