3a2-26a+30=-5

Solution for 3a2-26a+30=-5 equation:

3a^2-26a+30=-5

We move all terms to the left:

3a^2-26a+30-(-5)=0

We add all the numbers together, and all the variables

3a^2-26a+35=0

a = 3; b = -26; c = +35;
Δ = b2-4ac
Δ = -262-4·3·35
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-16}{2*3}=\frac{10}{6}
=1+2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+16}{2*3}=\frac{42}{6}
=7
$