3a2=3600

Solution for 3a2=3600 equation:

3a^2=3600

We move all terms to the left:

3a^2-(3600)=0

a = 3; b = 0; c = -3600;
Δ = b2-4ac
Δ = 02-4·3·(-3600)
Δ = 43200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{43200}=\sqrt{14400*3}=\sqrt{14400}*\sqrt{3}=120\sqrt{3}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120\sqrt{3}}{2*3}=\frac{0-120\sqrt{3}}{6}
=-\frac{120\sqrt{3}}{6}
=-20\sqrt{3}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120\sqrt{3}}{2*3}=\frac{0+120\sqrt{3}}{6}
=\frac{120\sqrt{3}}{6}
=20\sqrt{3}
$