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3a=2(a+5)+12
We move all terms to the left:
3a-(2(a+5)+12)=0
We calculate terms in parentheses: -(2(a+5)+12), so:We get rid of parentheses
2(a+5)+12
We multiply parentheses
2a+10+12
We add all the numbers together, and all the variables
2a+22
Back to the equation:
-(2a+22)
3a-2a-22=0
We add all the numbers together, and all the variables
a-22=0
We move all terms containing a to the left, all other terms to the right
a=22
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