3ab-(4bc-5ca+2ab)-(4ac-3cb)=

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Solution for 3ab-(4bc-5ca+2ab)-(4ac-3cb)= equation:


Simplifying
3ab + -1(4bc + -5ca + 2ab) + -1(4ac + -3cb) = 0

Reorder the terms:
3ab + -1(2ab + -5ac + 4bc) + -1(4ac + -3cb) = 0
3ab + (2ab * -1 + -5ac * -1 + 4bc * -1) + -1(4ac + -3cb) = 0
3ab + (-2ab + 5ac + -4bc) + -1(4ac + -3cb) = 0
3ab + -2ab + 5ac + -4bc + (4ac * -1 + -3bc * -1) = 0
3ab + -2ab + 5ac + -4bc + (-4ac + 3bc) = 0

Reorder the terms:
3ab + -2ab + 5ac + -4ac + -4bc + 3bc = 0

Combine like terms: 3ab + -2ab = 1ab
1ab + 5ac + -4ac + -4bc + 3bc = 0

Combine like terms: 5ac + -4ac = 1ac
1ab + 1ac + -4bc + 3bc = 0

Combine like terms: -4bc + 3bc = -1bc
1ab + 1ac + -1bc = 0

Solving
1ab + 1ac + -1bc = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'bc' to each side of the equation.
1ab + 1ac + -1bc + bc = 0 + bc

Combine like terms: -1bc + bc = 0
1ab + 1ac + 0 = 0 + bc
1ab + 1ac = 0 + bc
Remove the zero:
1ab + 1ac = bc

Combine like terms: bc + -1bc = 0
1ab + 1ac + -1bc = 0

The solution to this equation could not be determined.

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