3b(2b+-20)=358

Solution for 3b(2b+-20)=358 equation:

3b(2b+-20)=358

We move all terms to the left:

3b(2b+-20)-(358)=0

We add all the numbers together, and all the variables

3b(2b-20)-358=0

We multiply parentheses

6b^2-60b-358=0

a = 6; b = -60; c = -358;
Δ = b2-4ac
Δ = -602-4·6·(-358)
Δ = 12192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12192}=\sqrt{16*762}=\sqrt{16}*\sqrt{762}=4\sqrt{762}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{762}}{2*6}=\frac{60-4\sqrt{762}}{12}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{762}}{2*6}=\frac{60+4\sqrt{762}}{12}
$