3b(b=10)

Solution for 3b(b=10) equation:

3b(b=10)

We move all terms to the left:

3b(b-(10))=0

We multiply parentheses

3b^2-30b=0

a = 3; b = -30; c = 0;
Δ = b2-4ac
Δ = -302-4·3·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30}{2*3}=\frac{0}{6}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30}{2*3}=\frac{60}{6}
=10
$