3b*4-28*3+41b*2-15b+8/(3b-4)

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Solution for 3b*4-28*3+41b*2-15b+8/(3b-4) equation:


D( b )

3*b-4 = 0

3*b-4 = 0

3*b-4 = 0

3*b-4 = 0 // + 4

3*b = 4 // : 3

b = 4/3

b in (-oo:4/3) U (4/3:+oo)

8/(3*b-4)+3*4*b+2*41*b-(15*b)-(3*28) = 0

8/(3*b-4)+3*4*b+2*41*b-15*b-84 = 0

8/(3*b-4)+12*b+82*b-15*b-84 = 0

8/(3*b-4)+(12*b*(3*b-4))/(3*b-4)+(82*b*(3*b-4))/(3*b-4)+(-15*b*(3*b-4))/(3*b-4)+(-84*(3*b-4))/(3*b-4) = 0

12*b*(3*b-4)+82*b*(3*b-4)-15*b*(3*b-4)-84*(3*b-4)+8 = 0

36*b^2+246*b^2-45*b^2-48*b-328*b+60*b-252*b+8+336 = 0

282*b^2-45*b^2-376*b+60*b-252*b+8+336 = 0

237*b^2-316*b-252*b+8+336 = 0

237*b^2-568*b+344 = 0

237*b^2-568*b+344 = 0

237*b^2-568*b+344 = 0

DELTA = (-568)^2-(4*237*344)

DELTA = -3488

DELTA < 0

1 = 0

1/(3*b-4) = 0

1/(3*b-4) = 0 // * 3*b-4

1 = 0

b belongs to the empty set

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