3b+(b-10)+(b-10)=180

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Solution for 3b+(b-10)+(b-10)=180 equation: 



3b+(b-10)+(b-10)=180

We move all terms to the left:

3b+(b-10)+(b-10)-(180)=0

We get rid of parentheses

3b+b+b-10-10-180=0

We add all the numbers together, and all the variables

5b-200=0

We move all terms containing b to the left, all other terms to the right

5b=200

b=200/5

b=40

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