3b+(b-4)=3b+1

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Solution for 3b+(b-4)=3b+1 equation:


Simplifying
3b + (b + -4) = 3b + 1

Reorder the terms:
3b + (-4 + b) = 3b + 1

Remove parenthesis around (-4 + b)
3b + -4 + b = 3b + 1

Reorder the terms:
-4 + 3b + b = 3b + 1

Combine like terms: 3b + b = 4b
-4 + 4b = 3b + 1

Reorder the terms:
-4 + 4b = 1 + 3b

Solving
-4 + 4b = 1 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-4 + 4b + -3b = 1 + 3b + -3b

Combine like terms: 4b + -3b = 1b
-4 + 1b = 1 + 3b + -3b

Combine like terms: 3b + -3b = 0
-4 + 1b = 1 + 0
-4 + 1b = 1

Add '4' to each side of the equation.
-4 + 4 + 1b = 1 + 4

Combine like terms: -4 + 4 = 0
0 + 1b = 1 + 4
1b = 1 + 4

Combine like terms: 1 + 4 = 5
1b = 5

Divide each side by '1'.
b = 5

Simplifying
b = 5

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