3b+17=14b-68

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Solution for 3b+17=14b-68 equation:



3b+17=14b-68
We move all terms to the left:
3b+17-(14b-68)=0
We get rid of parentheses
3b-14b+68+17=0
We add all the numbers together, and all the variables
-11b+85=0
We move all terms containing b to the left, all other terms to the right
-11b=-85
b=-85/-11
b=7+8/11

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