3b+17=14b-68

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Solution for 3b+17=14b-68 equation: 



3b+17=14b-68

We move all terms to the left:

3b+17-(14b-68)=0

We get rid of parentheses

3b-14b+68+17=0

We add all the numbers together, and all the variables

-11b+85=0

We move all terms containing b to the left, all other terms to the right

-11b=-85

b=-85/-11

b=7+8/11

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