3b+1=4(-b-5)

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Solution for 3b+1=4(-b-5) equation: 



3b+1=4(-b-5)

We move all terms to the left:

3b+1-(4(-b-5))=0

We add all the numbers together, and all the variables

3b-(4(-1b-5))+1=0



We calculate terms in parentheses: -(4(-1b-5)), so:

4(-1b-5)

We multiply parentheses

-4b-20

Back to the equation:

-(-4b-20)



We get rid of parentheses

3b+4b+20+1=0

We add all the numbers together, and all the variables

7b+21=0

We move all terms containing b to the left, all other terms to the right

7b=-21

b=-21/7

b=-3

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