3b+1=b+11,b=

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Solution for 3b+1=b+11,b= equation: 



3b+1=b+11.b=

We move all terms to the left:

3b+1-(b+11.b)=0

We add all the numbers together, and all the variables

3b-(+12b)+1=0

We get rid of parentheses

3b-12b+1=0

We add all the numbers together, and all the variables

-9b+1=0

We move all terms containing b to the left, all other terms to the right

-9b=-1

b=-1/-9

b=1/9

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