3b+2(b+2)=13-(2b-5)

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Solution for 3b+2(b+2)=13-(2b-5) equation:


Simplifying
3b + 2(b + 2) = 13 + -1(2b + -5)

Reorder the terms:
3b + 2(2 + b) = 13 + -1(2b + -5)
3b + (2 * 2 + b * 2) = 13 + -1(2b + -5)
3b + (4 + 2b) = 13 + -1(2b + -5)

Reorder the terms:
4 + 3b + 2b = 13 + -1(2b + -5)

Combine like terms: 3b + 2b = 5b
4 + 5b = 13 + -1(2b + -5)

Reorder the terms:
4 + 5b = 13 + -1(-5 + 2b)
4 + 5b = 13 + (-5 * -1 + 2b * -1)
4 + 5b = 13 + (5 + -2b)

Combine like terms: 13 + 5 = 18
4 + 5b = 18 + -2b

Solving
4 + 5b = 18 + -2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '2b' to each side of the equation.
4 + 5b + 2b = 18 + -2b + 2b

Combine like terms: 5b + 2b = 7b
4 + 7b = 18 + -2b + 2b

Combine like terms: -2b + 2b = 0
4 + 7b = 18 + 0
4 + 7b = 18

Add '-4' to each side of the equation.
4 + -4 + 7b = 18 + -4

Combine like terms: 4 + -4 = 0
0 + 7b = 18 + -4
7b = 18 + -4

Combine like terms: 18 + -4 = 14
7b = 14

Divide each side by '7'.
b = 2

Simplifying
b = 2

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