3b+2(b+2)=2b-5

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Solution for 3b+2(b+2)=2b-5 equation: 



3b+2(b+2)=2b-5

We move all terms to the left:

3b+2(b+2)-(2b-5)=0

We multiply parentheses

3b+2b-(2b-5)+4=0

We get rid of parentheses

3b+2b-2b+5+4=0

We add all the numbers together, and all the variables

3b+9=0

We move all terms containing b to the left, all other terms to the right

3b=-9

b=-9/3

b=-3

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