3b+2(b+3)=57

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Solution for 3b+2(b+3)=57 equation: 



3b+2(b+3)=57

We move all terms to the left:

3b+2(b+3)-(57)=0

We multiply parentheses

3b+2b+6-57=0

We add all the numbers together, and all the variables

5b-51=0

We move all terms containing b to the left, all other terms to the right

5b=51

b=51/5

b=10+1/5

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