3b+2(b-3)=4

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Solution for 3b+2(b-3)=4 equation: 



3b+2(b-3)=4

We move all terms to the left:

3b+2(b-3)-(4)=0

We multiply parentheses

3b+2b-6-4=0

We add all the numbers together, and all the variables

5b-10=0

We move all terms containing b to the left, all other terms to the right

5b=10

b=10/5

b=2

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