3b+20=1b+150

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Solution for 3b+20=1b+150 equation: 



3b+20=1b+150

We move all terms to the left:

3b+20-(1b+150)=0

We add all the numbers together, and all the variables

3b-(b+150)+20=0

We get rid of parentheses

3b-b-150+20=0

We add all the numbers together, and all the variables

2b-130=0

We move all terms containing b to the left, all other terms to the right

2b=130

b=130/2

b=65

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