3b+2b-4b+3b=12

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Solution for 3b+2b-4b+3b=12 equation: 



3b+2b-4b+3b=12

We move all terms to the left:

3b+2b-4b+3b-(12)=0

We add all the numbers together, and all the variables

4b-12=0

We move all terms containing b to the left, all other terms to the right

4b=12

b=12/4

b=3

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