3b+3(b+4)=3(2b+4)

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Solution for 3b+3(b+4)=3(2b+4) equation:


Simplifying
3b + 3(b + 4) = 3(2b + 4)

Reorder the terms:
3b + 3(4 + b) = 3(2b + 4)
3b + (4 * 3 + b * 3) = 3(2b + 4)
3b + (12 + 3b) = 3(2b + 4)

Reorder the terms:
12 + 3b + 3b = 3(2b + 4)

Combine like terms: 3b + 3b = 6b
12 + 6b = 3(2b + 4)

Reorder the terms:
12 + 6b = 3(4 + 2b)
12 + 6b = (4 * 3 + 2b * 3)
12 + 6b = (12 + 6b)

Add '-12' to each side of the equation.
12 + -12 + 6b = 12 + -12 + 6b

Combine like terms: 12 + -12 = 0
0 + 6b = 12 + -12 + 6b
6b = 12 + -12 + 6b

Combine like terms: 12 + -12 = 0
6b = 0 + 6b
6b = 6b

Add '-6b' to each side of the equation.
6b + -6b = 6b + -6b

Combine like terms: 6b + -6b = 0
0 = 6b + -6b

Combine like terms: 6b + -6b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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