3b+3(b+5)=31+4b

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Solution for 3b+3(b+5)=31+4b equation: 



3b+3(b+5)=31+4b

We move all terms to the left:

3b+3(b+5)-(31+4b)=0

We add all the numbers together, and all the variables

3b+3(b+5)-(4b+31)=0

We multiply parentheses

3b+3b-(4b+31)+15=0

We get rid of parentheses

3b+3b-4b-31+15=0

We add all the numbers together, and all the variables

2b-16=0

We move all terms containing b to the left, all other terms to the right

2b=16

b=16/2

b=8

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