3b+3+1+5b=-4(5+9b)-4(b+6)

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Solution for 3b+3+1+5b=-4(5+9b)-4(b+6) equation: 



3b+3+1+5b=-4(5+9b)-4(b+6)

We move all terms to the left:

3b+3+1+5b-(-4(5+9b)-4(b+6))=0

We add all the numbers together, and all the variables

3b+5b-(-4(9b+5)-4(b+6))+3+1=0

We add all the numbers together, and all the variables

8b-(-4(9b+5)-4(b+6))+4=0



We calculate terms in parentheses: -(-4(9b+5)-4(b+6)), so:

-4(9b+5)-4(b+6)

We multiply parentheses

-36b-4b-20-24

We add all the numbers together, and all the variables

-40b-44

Back to the equation:

-(-40b-44)



We get rid of parentheses

8b+40b+44+4=0

We add all the numbers together, and all the variables

48b+48=0

We move all terms containing b to the left, all other terms to the right

48b=-48

b=-48/48

b=-1

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