3b+32=-8-7(2-3b)

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Solution for 3b+32=-8-7(2-3b) equation: 



3b+32=-8-7(2-3b)

We move all terms to the left:

3b+32-(-8-7(2-3b))=0

We add all the numbers together, and all the variables

3b-(-8-7(-3b+2))+32=0



We calculate terms in parentheses: -(-8-7(-3b+2)), so:

-8-7(-3b+2)

determiningTheFunctionDomain
-7(-3b+2)-8

We multiply parentheses

21b-14-8

We add all the numbers together, and all the variables

21b-22

Back to the equation:

-(21b-22)



We get rid of parentheses

3b-21b+22+32=0

We add all the numbers together, and all the variables

-18b+54=0

We move all terms containing b to the left, all other terms to the right

-18b=-54

b=-54/-18

b=+3

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