3b+4(2b-8)=78

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Solution for 3b+4(2b-8)=78 equation: 



3b+4(2b-8)=78

We move all terms to the left:

3b+4(2b-8)-(78)=0

We multiply parentheses

3b+8b-32-78=0

We add all the numbers together, and all the variables

11b-110=0

We move all terms containing b to the left, all other terms to the right

11b=110

b=110/11

b=10

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