3b+4(b+1)=-4b+3(1+4b

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Solution for 3b+4(b+1)=-4b+3(1+4b equation: 



3b+4(b+1)=-4b+3(1+4b

We move all terms to the left:

3b+4(b+1)-(-4b+3(1+4b)=0

We add all the numbers together, and all the variables

3b+4(b+1)-(-4b+3(4b+1)=0

We multiply parentheses

3b+4b-(-4b+3(4b+1)+4=0

We add all the numbers together, and all the variables

7b-(-4b+3(4b+1)+4=0

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