3b+4(b+1)=-4b+3(1+4b)

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Solution for 3b+4(b+1)=-4b+3(1+4b) equation: 



3b+4(b+1)=-4b+3(1+4b)

We move all terms to the left:

3b+4(b+1)-(-4b+3(1+4b))=0

We add all the numbers together, and all the variables

3b+4(b+1)-(-4b+3(4b+1))=0

We multiply parentheses

3b+4b-(-4b+3(4b+1))+4=0



We calculate terms in parentheses: -(-4b+3(4b+1)), so:

-4b+3(4b+1)

We multiply parentheses

-4b+12b+3

We add all the numbers together, and all the variables

8b+3

Back to the equation:

-(8b+3)



We add all the numbers together, and all the variables

7b-(8b+3)+4=0

We get rid of parentheses

7b-8b-3+4=0

We add all the numbers together, and all the variables

-1b+1=0

We move all terms containing b to the left, all other terms to the right

-b=-1

b=-1/-1

b=1

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