3b+4b=12+b

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Solution for 3b+4b=12+b equation: 



3b+4b=12+b

We move all terms to the left:

3b+4b-(12+b)=0

We add all the numbers together, and all the variables

3b+4b-(b+12)=0

We add all the numbers together, and all the variables

7b-(b+12)=0

We get rid of parentheses

7b-b-12=0

We add all the numbers together, and all the variables

6b-12=0

We move all terms containing b to the left, all other terms to the right

6b=12

b=12/6

b=2

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