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3b+5+2b=5(b+1)
We move all terms to the left:
3b+5+2b-(5(b+1))=0
We add all the numbers together, and all the variables
5b-(5(b+1))+5=0
We calculate terms in parentheses: -(5(b+1)), so:We get rid of parentheses
5(b+1)
We multiply parentheses
5b+5
Back to the equation:
-(5b+5)
5b-5b-5+5=0
We add all the numbers together, and all the variables
=0
b=0/1
b=0
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