3b+6=(b+2)

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Solution for 3b+6=(b+2) equation: 



3b+6=(b+2)

We move all terms to the left:

3b+6-((b+2))=0



We calculate terms in parentheses: -((b+2)), so:

(b+2)

We get rid of parentheses

b+2

Back to the equation:

-(b+2)



We get rid of parentheses

3b-b-2+6=0

We add all the numbers together, and all the variables

2b+4=0

We move all terms containing b to the left, all other terms to the right

2b=-4

b=-4/2

b=-2

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