3b+b=128

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Solution for 3b+b=128 equation: 



3b+b=128

We move all terms to the left:

3b+b-(128)=0

We add all the numbers together, and all the variables

4b-128=0

We move all terms containing b to the left, all other terms to the right

4b=128

b=128/4

b=32

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