3b-(1+4b)=8(b-6)+2

Solution for 3b-(1+4b)=8(b-6)+2 equation:

Simplifying
3b + -1(1 + 4b) = 8(b + -6) + 2
3b + (1 * -1 + 4b * -1) = 8(b + -6) + 2
3b + (-1 + -4b) = 8(b + -6) + 2

Reorder the terms:
-1 + 3b + -4b = 8(b + -6) + 2

Combine like terms: 3b + -4b = -1b
-1 + -1b = 8(b + -6) + 2

Reorder the terms:
-1 + -1b = 8(-6 + b) + 2
-1 + -1b = (-6 * 8 + b * 8) + 2
-1 + -1b = (-48 + 8b) + 2

Reorder the terms:
-1 + -1b = -48 + 2 + 8b

Combine like terms: -48 + 2 = -46
-1 + -1b = -46 + 8b

Solving
-1 + -1b = -46 + 8b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-8b' to each side of the equation.
-1 + -1b + -8b = -46 + 8b + -8b

Combine like terms: -1b + -8b = -9b
-1 + -9b = -46 + 8b + -8b

Combine like terms: 8b + -8b = 0
-1 + -9b = -46 + 0
-1 + -9b = -46

Add '1' to each side of the equation.
-1 + 1 + -9b = -46 + 1

Combine like terms: -1 + 1 = 0
0 + -9b = -46 + 1
-9b = -46 + 1

Combine like terms: -46 + 1 = -45
-9b = -45

Divide each side by '-9'.
b = 5

Simplifying
b = 5