3b-(b+1)=3(b-5)

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Solution for 3b-(b+1)=3(b-5) equation:


Simplifying
3b + -1(b + 1) = 3(b + -5)

Reorder the terms:
3b + -1(1 + b) = 3(b + -5)
3b + (1 * -1 + b * -1) = 3(b + -5)
3b + (-1 + -1b) = 3(b + -5)

Reorder the terms:
-1 + 3b + -1b = 3(b + -5)

Combine like terms: 3b + -1b = 2b
-1 + 2b = 3(b + -5)

Reorder the terms:
-1 + 2b = 3(-5 + b)
-1 + 2b = (-5 * 3 + b * 3)
-1 + 2b = (-15 + 3b)

Solving
-1 + 2b = -15 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-1 + 2b + -3b = -15 + 3b + -3b

Combine like terms: 2b + -3b = -1b
-1 + -1b = -15 + 3b + -3b

Combine like terms: 3b + -3b = 0
-1 + -1b = -15 + 0
-1 + -1b = -15

Add '1' to each side of the equation.
-1 + 1 + -1b = -15 + 1

Combine like terms: -1 + 1 = 0
0 + -1b = -15 + 1
-1b = -15 + 1

Combine like terms: -15 + 1 = -14
-1b = -14

Divide each side by '-1'.
b = 14

Simplifying
b = 14

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