3b-(b-5)=2(b+4)

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Solution for 3b-(b-5)=2(b+4) equation: 



3b-(b-5)=2(b+4)

We move all terms to the left:

3b-(b-5)-(2(b+4))=0

We get rid of parentheses

3b-b-(2(b+4))+5=0



We calculate terms in parentheses: -(2(b+4)), so:

2(b+4)

We multiply parentheses

2b+8

Back to the equation:

-(2b+8)



We add all the numbers together, and all the variables

2b-(2b+8)+5=0

We get rid of parentheses

2b-2b-8+5=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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