3b-1+2b=3(b-3)

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Solution for 3b-1+2b=3(b-3) equation: 



3b-1+2b=3(b-3)

We move all terms to the left:

3b-1+2b-(3(b-3))=0

We add all the numbers together, and all the variables

5b-(3(b-3))-1=0



We calculate terms in parentheses: -(3(b-3)), so:

3(b-3)

We multiply parentheses

3b-9

Back to the equation:

-(3b-9)



We get rid of parentheses

5b-3b+9-1=0

We add all the numbers together, and all the variables

2b+8=0

We move all terms containing b to the left, all other terms to the right

2b=-8

b=-8/2

b=-4

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