3b-12=7(-6-b)

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Solution for 3b-12=7(-6-b) equation: 



3b-12=7(-6-b)

We move all terms to the left:

3b-12-(7(-6-b))=0

We add all the numbers together, and all the variables

3b-(7(-1b-6))-12=0



We calculate terms in parentheses: -(7(-1b-6)), so:

7(-1b-6)

We multiply parentheses

-7b-42

Back to the equation:

-(-7b-42)



We get rid of parentheses

3b+7b+42-12=0

We add all the numbers together, and all the variables

10b+30=0

We move all terms containing b to the left, all other terms to the right

10b=-30

b=-30/10

b=-3

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