3b-27=63b+36

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Solution for 3b-27=63b+36 equation: 



3b-27=63b+36

We move all terms to the left:

3b-27-(63b+36)=0

We get rid of parentheses

3b-63b-36-27=0

We add all the numbers together, and all the variables

-60b-63=0

We move all terms containing b to the left, all other terms to the right

-60b=63

b=63/-60

b=-1+1/20

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