3b-3(b+1)=5(b-1)-5b

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Solution for 3b-3(b+1)=5(b-1)-5b equation:


Simplifying
3b + -3(b + 1) = 5(b + -1) + -5b

Reorder the terms:
3b + -3(1 + b) = 5(b + -1) + -5b
3b + (1 * -3 + b * -3) = 5(b + -1) + -5b
3b + (-3 + -3b) = 5(b + -1) + -5b

Reorder the terms:
-3 + 3b + -3b = 5(b + -1) + -5b

Combine like terms: 3b + -3b = 0
-3 + 0 = 5(b + -1) + -5b
-3 = 5(b + -1) + -5b

Reorder the terms:
-3 = 5(-1 + b) + -5b
-3 = (-1 * 5 + b * 5) + -5b
-3 = (-5 + 5b) + -5b

Combine like terms: 5b + -5b = 0
-3 = -5 + 0
-3 = -5

Solving
-3 = -5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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