3b-3(b-1)=2(3b-1)+6

Solution for 3b-3(b-1)=2(3b-1)+6 equation:

Simplifying
3b + -3(b + -1) = 2(3b + -1) + 6

Reorder the terms:
3b + -3(-1 + b) = 2(3b + -1) + 6
3b + (-1 * -3 + b * -3) = 2(3b + -1) + 6
3b + (3 + -3b) = 2(3b + -1) + 6

Reorder the terms:
3 + 3b + -3b = 2(3b + -1) + 6

Combine like terms: 3b + -3b = 0
3 + 0 = 2(3b + -1) + 6
3 = 2(3b + -1) + 6

Reorder the terms:
3 = 2(-1 + 3b) + 6
3 = (-1 * 2 + 3b * 2) + 6
3 = (-2 + 6b) + 6

Reorder the terms:
3 = -2 + 6 + 6b

Combine like terms: -2 + 6 = 4
3 = 4 + 6b

Solving
3 = 4 + 6b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-6b' to each side of the equation.
3 + -6b = 4 + 6b + -6b

Combine like terms: 6b + -6b = 0
3 + -6b = 4 + 0
3 + -6b = 4

Add '-3' to each side of the equation.
3 + -3 + -6b = 4 + -3

Combine like terms: 3 + -3 = 0
0 + -6b = 4 + -3
-6b = 4 + -3

Combine like terms: 4 + -3 = 1
-6b = 1

Divide each side by '-6'.
b = -0.1666666667

Simplifying
b = -0.1666666667