3b-33=5(7b+5)+6

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Solution for 3b-33=5(7b+5)+6 equation: 



3b-33=5(7b+5)+6

We move all terms to the left:

3b-33-(5(7b+5)+6)=0



We calculate terms in parentheses: -(5(7b+5)+6), so:

5(7b+5)+6

We multiply parentheses

35b+25+6

We add all the numbers together, and all the variables

35b+31

Back to the equation:

-(35b+31)



We get rid of parentheses

3b-35b-31-33=0

We add all the numbers together, and all the variables

-32b-64=0

We move all terms containing b to the left, all other terms to the right

-32b=64

b=64/-32

b=-2

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