3b-4(5)=b-5(15)

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Solution for 3b-4(5)=b-5(15) equation: 



3b-4(5)=b-5(15)

We move all terms to the left:

3b-4(5)-(b-5(15))=0

We get rid of parentheses

3b-b+515-45=0

We add all the numbers together, and all the variables

2b+470=0

We move all terms containing b to the left, all other terms to the right

2b=-470

b=-470/2

b=-235

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