3b-4(b+7)=2(b-9)-1

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Solution for 3b-4(b+7)=2(b-9)-1 equation: 



3b-4(b+7)=2(b-9)-1

We move all terms to the left:

3b-4(b+7)-(2(b-9)-1)=0

We multiply parentheses

3b-4b-(2(b-9)-1)-28=0



We calculate terms in parentheses: -(2(b-9)-1), so:

2(b-9)-1

We multiply parentheses

2b-18-1

We add all the numbers together, and all the variables

2b-19

Back to the equation:

-(2b-19)



We add all the numbers together, and all the variables

-1b-(2b-19)-28=0

We get rid of parentheses

-1b-2b+19-28=0

We add all the numbers together, and all the variables

-3b-9=0

We move all terms containing b to the left, all other terms to the right

-3b=9

b=9/-3

b=-3

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