3b-40=4+6(b-3)

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Solution for 3b-40=4+6(b-3) equation: 



3b-40=4+6(b-3)

We move all terms to the left:

3b-40-(4+6(b-3))=0



We calculate terms in parentheses: -(4+6(b-3)), so:

4+6(b-3)

determiningTheFunctionDomain
6(b-3)+4

We multiply parentheses

6b-18+4

We add all the numbers together, and all the variables

6b-14

Back to the equation:

-(6b-14)



We get rid of parentheses

3b-6b+14-40=0

We add all the numbers together, and all the variables

-3b-26=0

We move all terms containing b to the left, all other terms to the right

-3b=26

b=26/-3

b=-8+2/3

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