3b-43+b+5=b+49

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Solution for 3b-43+b+5=b+49 equation: 



3b-43+b+5=b+49

We move all terms to the left:

3b-43+b+5-(b+49)=0

We add all the numbers together, and all the variables

4b-(b+49)-38=0

We get rid of parentheses

4b-b-49-38=0

We add all the numbers together, and all the variables

3b-87=0

We move all terms containing b to the left, all other terms to the right

3b=87

b=87/3

b=29

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