3b-4=-4(b+1)+7b

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Solution for 3b-4=-4(b+1)+7b equation:



3b-4=-4(b+1)+7b
We move all terms to the left:
3b-4-(-4(b+1)+7b)=0
We calculate terms in parentheses: -(-4(b+1)+7b), so:
-4(b+1)+7b
We add all the numbers together, and all the variables
7b-4(b+1)
We multiply parentheses
7b-4b-4
We add all the numbers together, and all the variables
3b-4
Back to the equation:
-(3b-4)
We get rid of parentheses
3b-3b+4-4=0
We add all the numbers together, and all the variables
=0
b=0/1
b=0

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