3b-4=2(b-2)+b

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Solution for 3b-4=2(b-2)+b equation: 



3b-4=2(b-2)+b

We move all terms to the left:

3b-4-(2(b-2)+b)=0



We calculate terms in parentheses: -(2(b-2)+b), so:

2(b-2)+b

We add all the numbers together, and all the variables

b+2(b-2)

We multiply parentheses

b+2b-4

We add all the numbers together, and all the variables

3b-4

Back to the equation:

-(3b-4)



We get rid of parentheses

3b-3b+4-4=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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