3b-56=b+62

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Solution for 3b-56=b+62 equation: 



3b-56=b+62

We move all terms to the left:

3b-56-(b+62)=0

We get rid of parentheses

3b-b-62-56=0

We add all the numbers together, and all the variables

2b-118=0

We move all terms containing b to the left, all other terms to the right

2b=118

b=118/2

b=59

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