3b-5=27

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Solution for 3b-5=27 equation: 



3b-5=27

We move all terms to the left:

3b-5-(27)=0

We add all the numbers together, and all the variables

3b-32=0

We move all terms containing b to the left, all other terms to the right

3b=32

b=32/3

b=10+2/3

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