3b-67=b-11

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Solution for 3b-67=b-11 equation: 



3b-67=b-11

We move all terms to the left:

3b-67-(b-11)=0

We get rid of parentheses

3b-b+11-67=0

We add all the numbers together, and all the variables

2b-56=0

We move all terms containing b to the left, all other terms to the right

2b=56

b=56/2

b=28

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