3b-6=3(b-2)

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Solution for 3b-6=3(b-2) equation: 



3b-6=3(b-2)

We move all terms to the left:

3b-6-(3(b-2))=0



We calculate terms in parentheses: -(3(b-2)), so:

3(b-2)

We multiply parentheses

3b-6

Back to the equation:

-(3b-6)



We get rid of parentheses

3b-3b+6-6=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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