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b in (-oo:+oo)
(3*b)/2-4 = (2*b)/3-(2/3) // - (2*b)/3-(2/3)
(3*b)/2-((2*b)/3)+2/3-4 = 0
(3*b)/2+(-2/3)*b+2/3-4 = 0
5/6*b-10/3 = 0 // + 10/3
5/6*b = 10/3 // : 5/6
b = 10/3/5/6
b = 4
b = 4
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